3^(4x-5)=((1)/(27))^(2x+10)

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Solution for 3^(4x-5)=((1)/(27))^(2x+10) equation: 



3^(4x-5)=((1)/(27))^(2x+10)

We move all terms to the left:

3^(4x-5)-(((1)/(27))^(2x+10))=0



Domain of the equation: 27)^(2x+10))!=0

x∈R



We add all the numbers together, and all the variables

3^(4x-5)-((+1/27)^(2x+10))=0

We multiply all the terms by the denominator


(3^(4x-5))*27)^(2x+1+10))-((=0

We add all the numbers together, and all the variables

(3^(4x-5))*27)^(2x+11))-((=0

We add all the numbers together, and all the variables

(3^(4x-5))*27)^(2x=0

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